What are the solutions to the equation d^3+d^2+4d+4=0 ?

The solutions to the equation d^3+d^2+4d+4=0 are d=-1,d=2i,d=-2i

Find the zeros of d^3+d^2+4d+4=0

The zeros of d^3+d^2+4d+4=0 are d=-1,d=2i,d=-2i

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d^{3} + d^{2} + 4 d + 4 = 0

d = - 1, d = 2 i, d = - 2 i

Solution steps

d^{3} + d^{2} + 4 d + 4 = 0

Factor

d^{3} + d^{2} + 4 d + 4 : (d + 1) (d^{2} + 4)

(d + 1) (d^{2} + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

d + 1 = 0 or d^{2} + 4 = 0

Solve

d + 1 = 0 : d = - 1

Solve

d^{2} + 4 = 0 : d = 2 i, d = - 2 i

The solutions are

d = - 1, d = 2 i, d = - 2 i

x^{5} - x - 1 = 0

x^{3} - 2 x^{3} + 1 = 28

(x + 4)^{2} (x - 3)^{2} = (x + 5)^{2}

x^{3} = x^{5}

5 x^{3} - 5 = 0

What are the solutions to the equation d^3+d^2+4d+4=0 ?
The solutions to the equation d^3+d^2+4d+4=0 are d=-1,d=2i,d=-2i
Find the zeros of d^3+d^2+4d+4=0
The zeros of d^3+d^2+4d+4=0 are d=-1,d=2i,d=-2i