What are the solutions to the equation 2=(1+x)^{10} ?

The solutions to the equation 2=(1+x)^{10} are x=\sqrt[10]{2}-1,x=-\sqrt[10]{2}-1

Find the zeros of 2=(1+x)^{10}

The zeros of 2=(1+x)^{10} are x=\sqrt[10]{2}-1,x=-\sqrt[10]{2}-1

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2 = (1 + x)^{10}

Decimal Notation

x = 0.07177 \dots, x = - 2.07177 \dots

Solution steps

2 = (1 + x)^{10}

Switch sides

(1 + x)^{10} = 2

For

(g (x))^{n} = f (a)

, n is even, the solutions are

Solve

The solutions are

n^{3} - n = 720

x^{3} - 9 x^{2} + 3 x + 45 = 0

(x^{2} - 1) (x^{2} - 11) (x^{2} - 21) (x^{2} - 31) = - 4224

(3 x + 1)^{3} = 100

(4 x - 1)^{5} = 1

What are the solutions to the equation 2=(1+x)^{10} ?
The solutions to the equation 2=(1+x)^{10} are x=\sqrt[10]{2}-1,x=-\sqrt[10]{2}-1
Find the zeros of 2=(1+x)^{10}
The zeros of 2=(1+x)^{10} are x=\sqrt[10]{2}-1,x=-\sqrt[10]{2}-1