What are the solutions to the equation 0=4x^3-4x^2-4 ?

The solutions to the equation 0=4x^3-4x^2-4 are x\approx 1.46557…

Find the zeros of 0=4x^3-4x^2-4

The zeros of 0=4x^3-4x^2-4 are x\approx 1.46557…

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0 = 4 x^{3} - 4 x^{2} - 4

x \approx 1.46557 \dots

Solution steps

0 = 4 x^{3} - 4 x^{2} - 4

Switch sides

4 x^{3} - 4 x^{2} - 4 = 0

Find one solution for

4 x^{3} - 4 x^{2} - 4 = 0

using Newton-Raphson:

x \approx 1.46557 \dots

Apply long division:

\frac{4 x ^{3} - 4 x ^{2} - 4}{x - 1.46557 \dots} = 4 x^{2} + 1.86228 \dots x + 2.72931 \dots

4 x^{2} + 1.86228 \dots x + 2.72931 \dots \approx 0

Find one solution for

4 x^{2} + 1.86228 \dots x + 2.72931 \dots = 0

using Newton-Raphson:

No Solution for

x \in R

The solution is

x \approx 1.46557 \dots

- 4 x^{3} - 4 x = 0

2 y^{3} + y^{2} - 13 y - 6 y = \frac{2}{3}

(x + 1) (- 3 x^{2} + 9 x + 30) = 0

(x^{2} - x) + 1 = (x^{3} - 2)

x, 2 f - f (\frac{1}{x}) = ln (x^{3})

What are the solutions to the equation 0=4x^3-4x^2-4 ?
The solutions to the equation 0=4x^3-4x^2-4 are x\approx 1.46557…
Find the zeros of 0=4x^3-4x^2-4
The zeros of 0=4x^3-4x^2-4 are x\approx 1.46557…