What is 1/(x+1)+1/(x+8)<= 0 ?

The solution to 1/(x+1)+1/(x+8)<= 0 is x<-8\lor-9/2 <= x<-1

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1/(x+1)+1/(x+8)<= 0

\frac{1}{x + 1} + \frac{1}{x + 8} \leq 0

x < - 8 or - \frac{9}{2} \leq x < - 1

Solution steps

\frac{1}{x + 1} + \frac{1}{x + 8} \leq 0

Rewrite in standard form

\frac{2 x + 9}{( x + 1 ) ( x + 8 )} \leq 0

Identify the intervals

x < - 8 or - \frac{9}{2} \leq x < - 1

v - 14 \leq - 8

3 z + 20 = 2 z + 5

2 x + 5 = 4 x - 1

(3 x)^{\frac{1}{2}}

\frac{40 x ^{2} y ^{6}}{8 x ^{2} y ^{2}}

What is 1/(x+1)+1/(x+8)<= 0 ?
The solution to 1/(x+1)+1/(x+8)<= 0 is x<-8\lor-9/2 <= x<-1