What are the solutions to the equation solvefor a,a^5+b^5=4806 ?

The solutions to the equation solvefor a,a^5+b^5=4806 are a=\sqrt[5]{4806-b^5}

Find the zeros of solvefor a,a^5+b^5=4806

The zeros of solvefor a,a^5+b^5=4806 are a=\sqrt[5]{4806-b^5}

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solve for

a, a^{5} + b^{5} = 4806

Solution steps

a^{5} + b^{5} = 4806

Move

b^{5}

to the right side

a^{5} = 4806 - b^{5}

For

x^{n} = f (a)

, n is odd, the solution is

5 x^{3} = 45 x

x^{3} + 3 x^{2} + 4 x - 11 = 0

x^{3} - 18 \cdot x^{2} + 81 \cdot x - 108 = 0

m^{3} + m^{2} - 2 = 0

(x^{2} - 3 x)^{2} - (x^{2} - 3)^{2} - 8 = 0

What are the solutions to the equation solvefor a,a^5+b^5=4806 ?
The solutions to the equation solvefor a,a^5+b^5=4806 are a=\sqrt[5]{4806-b^5}
Find the zeros of solvefor a,a^5+b^5=4806
The zeros of solvefor a,a^5+b^5=4806 are a=\sqrt[5]{4806-b^5}