What are the solutions to the equation 43-2(x+3)^4=11 ?

The solutions to the equation 43-2(x+3)^4=11 are x=-1,x=-5

Find the zeros of 43-2(x+3)^4=11

The zeros of 43-2(x+3)^4=11 are x=-1,x=-5

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43 - 2 (x + 3)^{4} = 11

x = - 1, x = - 5

Solution steps

43 - 2 (x + 3)^{4} = 11

Move

43

to the right side

- 2 (x + 3)^{4} = - 32

Divide both sides by

- 2

(x + 3)^{4} = 16

For

(g (x))^{n} = f (a)

, n is even, the solutions are

Solve

The solutions are

x = - 1, x = - 5

(x + 11)^{4} = 169

2 x^{4} - 13 x^{3} + 28 x^{2} = 23 x - 6

x, lo g_{10} (y) = - x^{3}

(x^{2} - 3 x + 2) (x^{2} - 9 x + 20) (x^{2} - 9 x + 18) = 720

- a^{3} + 3 a^{2} - 3 a + 1 = 0

What are the solutions to the equation 43-2(x+3)^4=11 ?
The solutions to the equation 43-2(x+3)^4=11 are x=-1,x=-5
Find the zeros of 43-2(x+3)^4=11
The zeros of 43-2(x+3)^4=11 are x=-1,x=-5