What are the solutions to the equation m^1m^2=-1 ?

The solutions to the equation m^1m^2=-1 are m=-1,m= 1/2-(sqrt(3))/2 i,m= 1/2+(sqrt(3))/2 i

Find the zeros of m^1m^2=-1

The zeros of m^1m^2=-1 are m=-1,m= 1/2-(sqrt(3))/2 i,m= 1/2+(sqrt(3))/2 i

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m^{1} m^{2} = - 1

m = - 1, m = \frac{1}{2} - \frac{3}{2} i, m = \frac{1}{2} + \frac{3}{2} i

Solution steps

m^{1} m^{2} = - 1

Simplify

m^{3} = - 1

For

x^{3} = f (a)

the solutions are

Simplify

m = - 1, m = \frac{1}{2} - \frac{3}{2} i, m = \frac{1}{2} + \frac{3}{2} i

3 x^{4} - 15 x^{2} + 29 = 0

a^{3} - 3 a^{2} = 240

s^{5} - s^{3} - s^{2} + 1 = 0

a^{5} = 7

x^{4} + x^{3} + x + 1 = 4 x^{2}

What are the solutions to the equation m^1m^2=-1 ?
The solutions to the equation m^1m^2=-1 are m=-1,m= 1/2-(sqrt(3))/2 i,m= 1/2+(sqrt(3))/2 i
Find the zeros of m^1m^2=-1
The zeros of m^1m^2=-1 are m=-1,m= 1/2-(sqrt(3))/2 i,m= 1/2+(sqrt(3))/2 i