What are the solutions to the equation (2x^2-3)^2=49 ?

The solutions to the equation (2x^2-3)^2=49 are x=sqrt(5),x=-sqrt(5),x=sqrt(2)i,x=-sqrt(2)i

Find the zeros of (2x^2-3)^2=49

The zeros of (2x^2-3)^2=49 are x=sqrt(5),x=-sqrt(5),x=sqrt(2)i,x=-sqrt(2)i

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(2 x^{2} - 3)^{2} = 49

x = 5, x = - 5, x = 2 i, x = - 2 i

Solution steps

(2 x^{2} - 3)^{2} = 49

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x^{2} - 3 = 49 : x = 5, x = - 5

Solve

2 x^{2} - 3 = - 49 : x = 2 i, x = - 2 i

The solutions are

x = 5, x = - 5, x = 2 i, x = - 2 i

10 r + 1 = [1 + r]^{6}

1 - x^{9} = (1 - x) (1 + x + x^{2})

x^{4} - 81 = 0

x^{4} - 6 x^{2} + 5 = 0

(x) = 3 x^{3} + x^{2} - 22 x + 9

What are the solutions to the equation (2x^2-3)^2=49 ?
The solutions to the equation (2x^2-3)^2=49 are x=sqrt(5),x=-sqrt(5),x=sqrt(2)i,x=-sqrt(2)i
Find the zeros of (2x^2-3)^2=49
The zeros of (2x^2-3)^2=49 are x=sqrt(5),x=-sqrt(5),x=sqrt(2)i,x=-sqrt(2)i