What are the solutions to the equation (x+1)^3+(x-1)^3=0 ?

The solutions to the equation (x+1)^3+(x-1)^3=0 are x=0,x=sqrt(3)i,x=-sqrt(3)i

Find the zeros of (x+1)^3+(x-1)^3=0

The zeros of (x+1)^3+(x-1)^3=0 are x=0,x=sqrt(3)i,x=-sqrt(3)i

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(x + 1)^{3} + (x - 1)^{3} = 0

x = 0, x = 3 i, x = - 3 i

Solution steps

(x + 1)^{3} + (x - 1)^{3} = 0

Factor

(x + 1)^{3} + (x - 1)^{3} : 2 x (x^{2} + 3)

2 x (x^{2} + 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x^{2} + 3 = 0

Solve

x^{2} + 3 = 0 : x = 3 i, x = - 3 i

The solutions are

x = 0, x = 3 i, x = - 3 i

x^{4} - 14 x^{3} + 48 x^{2} = 0

- 2 x^{3} + 6 x^{2} + 9 = 0

2 x^{4} + 48 x^{2} - 15 x + 320 = 0

x^{4} - 5 x^{2} - 4 = 0

x^{4} = 81

What are the solutions to the equation (x+1)^3+(x-1)^3=0 ?
The solutions to the equation (x+1)^3+(x-1)^3=0 are x=0,x=sqrt(3)i,x=-sqrt(3)i
Find the zeros of (x+1)^3+(x-1)^3=0
The zeros of (x+1)^3+(x-1)^3=0 are x=0,x=sqrt(3)i,x=-sqrt(3)i