What are the solutions to the equation (3x-2)^5=24 ?

The solutions to the equation (3x-2)^5=24 are x=(\sqrt[5]{24}+2)/3

Find the zeros of (3x-2)^5=24

The zeros of (3x-2)^5=24 are x=(\sqrt[5]{24}+2)/3

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(3 x - 2)^{5} = 24

Decimal Notation

x = 1.29605 \dots

Solution steps

(3 x - 2)^{5} = 24

For

(g (x))^{n} = f (a)

, n is odd, the solution is

Solve

The solution is

(2 + b) (11 b - 2 b^{2}) + 189 = 0

x, x^{4} y^{3} - 2 x y^{4} = x y^{3}

x^{3} - 2 x - 3 = 0

x^{3} - 5 x^{2} + 9 x - 45 = 0

19 s^{3} = 1

What are the solutions to the equation (3x-2)^5=24 ?
The solutions to the equation (3x-2)^5=24 are x=(\sqrt[5]{24}+2)/3
Find the zeros of (3x-2)^5=24
The zeros of (3x-2)^5=24 are x=(\sqrt[5]{24}+2)/3