What are the solutions to the equation x^3-4x+2=0 ?

The solutions to the equation x^3-4x+2=0 are x\approx 0.53918…,x\approx 1.67513…,x\approx-2.21431…

Find the zeros of x^3-4x+2=0

The zeros of x^3-4x+2=0 are x\approx 0.53918…,x\approx 1.67513…,x\approx-2.21431…

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x^{3} - 4 x + 2 = 0

x \approx 0.53918 \dots, x \approx 1.67513 \dots, x \approx - 2.21431 \dots

Solution steps

x^{3} - 4 x + 2 = 0

Find one solution for

x^{3} - 4 x + 2 = 0

using Newton-Raphson:

x \approx 0.53918 \dots

Apply long division:

\frac{x ^{3} - 4 x + 2}{x - 0.53918 \dots} = x^{2} + 0.53918 \dots x - 3.70927 \dots

x^{2} + 0.53918 \dots x - 3.70927 \dots \approx 0

Find one solution for

x^{2} + 0.53918 \dots x - 3.70927 \dots = 0

using Newton-Raphson:

x \approx 1.67513 \dots

Apply long division:

\frac{x ^{2} + 0.53918 \dots x - 3.70927 \dots}{x - 1.67513 \dots} = x + 2.21431 \dots

x + 2.21431 \dots \approx 0

x \approx - 2.21431 \dots

The solutions are

x \approx 0.53918 \dots, x \approx 1.67513 \dots, x \approx - 2.21431 \dots

x^{3} - 3 x^{2} + 2 x = 0

19 x^{3} = 1

x^{3} + 18 x^{2} - 83.5 x + 37 = 0

(x^{2} - x - 3)^{2} - x^{3} = 17

(2 x^{2} - 5)^{2} = 39 + 10 (2 x^{2} - 5)

What are the solutions to the equation x^3-4x+2=0 ?
The solutions to the equation x^3-4x+2=0 are x\approx 0.53918…,x\approx 1.67513…,x\approx-2.21431…
Find the zeros of x^3-4x+2=0
The zeros of x^3-4x+2=0 are x\approx 0.53918…,x\approx 1.67513…,x\approx-2.21431…