What are the solutions to the equation 6-(p^2)/8 =-4 ?

The solutions to the equation 6-(p^2)/8 =-4 are p=4sqrt(5),p=-4sqrt(5)

Find the zeros of 6-(p^2)/8 =-4

The zeros of 6-(p^2)/8 =-4 are p=4sqrt(5),p=-4sqrt(5)

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6 - \frac{p ^{2}}{8} = - 4

p = 45, p = - 45

Solution steps

6 - \frac{p ^{2}}{8} = - 4

Move

6

to the right side

- \frac{p ^{2}}{8} = - 10

Multiply both sides by

8

- p^{2} = - 80

Divide both sides by

- 1

p^{2} = 80

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

p = 80, p = - 80

80 = 45

- 80 = - 45

p = 45, p = - 45

\frac{d}{- 12} = 144

6125

\frac{x ^{5} - 7 x ^{4} + 33 x ^{2} - 34 x}{17}

- \frac{2}{7} + \frac{3}{5}

\frac{\frac{1}{3}}{1 - \frac{1}{3}}

What are the solutions to the equation 6-(p^2)/8 =-4 ?
The solutions to the equation 6-(p^2)/8 =-4 are p=4sqrt(5),p=-4sqrt(5)
Find the zeros of 6-(p^2)/8 =-4
The zeros of 6-(p^2)/8 =-4 are p=4sqrt(5),p=-4sqrt(5)