What are the solutions to the equation r^3+10r^2+33r-29=0 ?

The solutions to the equation r^3+10r^2+33r-29=0 are r\approx 0.71350…

Find the zeros of r^3+10r^2+33r-29=0

The zeros of r^3+10r^2+33r-29=0 are r\approx 0.71350…

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r^{3} + 10 r^{2} + 33 r - 29 = 0

r \approx 0.71350 \dots

Solution steps

r^{3} + 10 r^{2} + 33 r - 29 = 0

Find one solution for

r^{3} + 10 r^{2} + 33 r - 29 = 0

using Newton-Raphson:

r \approx 0.71350 \dots

Apply long division:

\frac{r ^{3} + 10 r ^{2} + 33 r - 29}{r - 0.71350 \dots} = r^{2} + 10.71350 \dots r + 40.64418 \dots

r^{2} + 10.71350 \dots r + 40.64418 \dots \approx 0

Find one solution for

r^{2} + 10.71350 \dots r + 40.64418 \dots = 0

using Newton-Raphson:

No Solution for

r \in R

The solution is

r \approx 0.71350 \dots

1.477 = (1 + g)^{5}

(x + 2) (2 x^{2} - x - 1) = 0

320 = 62500 \cdot (\frac{1 - r}{100})^{3}

x^{4} + 4 x^{3} + 8 x^{2} + 8 x + 4 = 0

x^{4} + 3 x^{2} + 4 = 0

What are the solutions to the equation r^3+10r^2+33r-29=0 ?
The solutions to the equation r^3+10r^2+33r-29=0 are r\approx 0.71350…
Find the zeros of r^3+10r^2+33r-29=0
The zeros of r^3+10r^2+33r-29=0 are r\approx 0.71350…