What are the solutions to the equation (4x+4a)^3=0 ?

The solutions to the equation (4x+4a)^3=0 are x=-a

Find the zeros of (4x+4a)^3=0

The zeros of (4x+4a)^3=0 are x=-a

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(4 x + 4 a)^{3} = 0

x = - a

Solution steps

(4 x + 4 a)^{3} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

Solve

4 x + 4 a = 0 : x = - a

The solution is

x = - a

4 x^{3} + x = x^{2}

x^{8} = 729

4 x + 2 x^{2} + 8 x^{3} = 10

4 x^{4} - 9 x^{2} + 3 = 0

y^{4} - 10 y^{3} + 5 y^{2} + 100 y + 100 = 0

What are the solutions to the equation (4x+4a)^3=0 ?
The solutions to the equation (4x+4a)^3=0 are x=-a
Find the zeros of (4x+4a)^3=0
The zeros of (4x+4a)^3=0 are x=-a