What are the solutions to the equation x^1-2x^2+x^3-3x^4=1 ?

The solutions to the equation x^1-2x^2+x^3-3x^4=1 are No Solution for x\in\mathbb{R}

Find the zeros of x^1-2x^2+x^3-3x^4=1

The zeros of x^1-2x^2+x^3-3x^4=1 are No Solution for x\in\mathbb{R}

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x^{1} - 2 x^{2} + x^{3} - 3 x^{4} = 1

No Solution for x \in R

Solution steps

x^{1} - 2 x^{2} + x^{3} - 3 x^{4} = 1

Refine

x - 2 x^{2} + x^{3} - 3 x^{4} = 1

Move

1

to the left side

x - 2 x^{2} + x^{3} - 3 x^{4} - 1 = 0

Write in the standard form

a_{n} x^{n} + \dots + a_{1} x + a_{0} = 0

- 3 x^{4} + x^{3} - 2 x^{2} + x - 1 = 0

Find one solution for

- 3 x^{4} + x^{3} - 2 x^{2} + x - 1 = 0

using Newton-Raphson:

No Solution for

x \in R

The solution is

No Solution for x \in R

(x + 3)^{4} + (x + 5)^{4} = 16

3 x^{3} - 8 x^{2} + 8 = 5 x + 5

(m^{4} + 25 m^{2} + 25) - 12 m^{2} - 60 m - 49 = 0

x^{4} + 2 x^{3} - 8 x - 16 = 0

(3 x - 4)^{10} - 3 = 1021

What are the solutions to the equation x^1-2x^2+x^3-3x^4=1 ?
The solutions to the equation x^1-2x^2+x^3-3x^4=1 are No Solution for x\in\mathbb{R}
Find the zeros of x^1-2x^2+x^3-3x^4=1
The zeros of x^1-2x^2+x^3-3x^4=1 are No Solution for x\in\mathbb{R}