What are the solutions to the equation ((x+2)/3)^4=128 ?

The solutions to the equation ((x+2)/3)^4=128 are x=6\sqrt[4]{8}-2,x=-6\sqrt[4]{8}-2

Find the zeros of ((x+2)/3)^4=128

The zeros of ((x+2)/3)^4=128 are x=6\sqrt[4]{8}-2,x=-6\sqrt[4]{8}-2

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(\frac{x + 2}{3})^{4} = 128

Decimal Notation

x = 8.09075 \dots, x = - 12.09075 \dots

Solution steps

(\frac{x + 2}{3})^{4} = 128

For

(g (x))^{n} = f (a)

, n is even, the solutions are

Solve

The solutions are

x^{4} - 4 x + 4 = 0

a^{3} - 6 a^{2} + 15 a + 10 = 0

4 x^{3} - 4 x^{2} - x + 1 = 0

x^{3} + 9 x^{2} + 27 + 19 = 0

x^{3} - 2 x - 4 = 0

What are the solutions to the equation ((x+2)/3)^4=128 ?
The solutions to the equation ((x+2)/3)^4=128 are x=6\sqrt[4]{8}-2,x=-6\sqrt[4]{8}-2
Find the zeros of ((x+2)/3)^4=128
The zeros of ((x+2)/3)^4=128 are x=6\sqrt[4]{8}-2,x=-6\sqrt[4]{8}-2