What is (-20k^4-26k^3)/(12k^4+8k^3) ?

The solution to (-20k^4-26k^3)/(12k^4+8k^3) is -(10k+13)/(2(3k+2))

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simplify (-20k^4-26k^3)/(12k^4+8k^3)

simplify

\frac{- 20 k ^{4} - 26 k ^{3}}{12 k ^{4} + 8 k ^{3}}

- \frac{10 k + 13}{2 ( 3 k + 2 )}

Solution steps

\frac{- 20 k ^{4} - 26 k ^{3}}{12 k ^{4} + 8 k ^{3}}

Factor

- 20 k^{4} - 26 k^{3} : - 2 k^{3} (10 k + 13)

= \frac{- 2 k ^{3} ( 10 k + 13 )}{12 k ^{4} + 8 k ^{3}}

Factor

12 k^{4} + 8 k^{3} : 4 k^{3} (3 k + 2)

= \frac{- 2 k ^{3} ( 10 k + 13 )}{4 k ^{3} ( 3 k + 2 )}

Cancel the common factor:

k^{3}

= \frac{- 2 ( 10 k + 13 )}{4 ( 3 k + 2 )}

Factor the number:

4 = 2 \cdot 2

= \frac{- 2 ( 10 k + 13 )}{2 \cdot 2 ( 3 k + 2 )}

Cancel the common factor:

2

= \frac{- ( 10 k + 13 )}{2 ( 3 k + 2 )}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{10 k + 13}{2 ( 3 k + 2 )}

\frac{4}{x} - 3 < \frac{2}{x} - 7

x^{3} - 5 x^{2} + 2 x + 8

- x + 7 > 3 and x - 12 < - 10

\frac{a y - a x + b y - b x}{2 a y - b y - 2 a x + b x}

(4 t)^{2}

What is (-20k^4-26k^3)/(12k^4+8k^3) ?
The solution to (-20k^4-26k^3)/(12k^4+8k^3) is -(10k+13)/(2(3k+2))