What are the solutions to the equation 6=20+12t^2-t^3 ?

The solutions to the equation 6=20+12t^2-t^3 are t\approx 12.09569…

Find the zeros of 6=20+12t^2-t^3

The zeros of 6=20+12t^2-t^3 are t\approx 12.09569…

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6 = 20 + 12 t^{2} - t^{3}

t \approx 12.09569 \dots

Solution steps

6 = 20 + 12 t^{2} - t^{3}

Switch sides

20 + 12 t^{2} - t^{3} = 6

Move

6

to the left side

- t^{3} + 12 t^{2} + 14 = 0

Find one solution for

- t^{3} + 12 t^{2} + 14 = 0

using Newton-Raphson:

t \approx 12.09569 \dots

Apply long division:

\frac{- t ^{3} + 12 t ^{2} + 14}{t - 12.09569 \dots} = - t^{2} - 0.09569 \dots t - 1.15743 \dots

- t^{2} - 0.09569 \dots t - 1.15743 \dots \approx 0

Find one solution for

- t^{2} - 0.09569 \dots t - 1.15743 \dots = 0

using Newton-Raphson:

No Solution for

t \in R

The solution is

t \approx 12.09569 \dots

x^{6} - 5 x^{3} - 16 = 0

(x - 5) \cdot x^{2} = 14

2 x^{3} = 0

m^{4} + 5 m^{2} + 4 = 0

3 x^{3} - 2 x^{2} - 7 x - 2 = 0

What are the solutions to the equation 6=20+12t^2-t^3 ?
The solutions to the equation 6=20+12t^2-t^3 are t\approx 12.09569…
Find the zeros of 6=20+12t^2-t^3
The zeros of 6=20+12t^2-t^3 are t\approx 12.09569…