What are the solutions to the equation m^3+m^2+4m+4=0 ?

The solutions to the equation m^3+m^2+4m+4=0 are m=-1,m=2i,m=-2i

Find the zeros of m^3+m^2+4m+4=0

The zeros of m^3+m^2+4m+4=0 are m=-1,m=2i,m=-2i

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m^{3} + m^{2} + 4 m + 4 = 0

m = - 1, m = 2 i, m = - 2 i

Solution steps

m^{3} + m^{2} + 4 m + 4 = 0

Factor

m^{3} + m^{2} + 4 m + 4 : (m + 1) (m^{2} + 4)

(m + 1) (m^{2} + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

m + 1 = 0 or m^{2} + 4 = 0

Solve

m + 1 = 0 : m = - 1

Solve

m^{2} + 4 = 0 : m = 2 i, m = - 2 i

The solutions are

m = - 1, m = 2 i, m = - 2 i

4 (7) = 1 + 64 (2 - n)^{3}

x^{4} - 5 x^{3} + 5 x^{2} + 5 x - 6 = 0

x, 3 y^{2} = (2 x + 3)^{3}

2 x^{3} = 388

- 5 x^{3} + 35 x - 30 = 0

What are the solutions to the equation m^3+m^2+4m+4=0 ?
The solutions to the equation m^3+m^2+4m+4=0 are m=-1,m=2i,m=-2i
Find the zeros of m^3+m^2+4m+4=0
The zeros of m^3+m^2+4m+4=0 are m=-1,m=2i,m=-2i