What are the solutions to the equation (x+2)(2x^2-5x)-x^3=8 ?

The solutions to the equation (x+2)(2x^2-5x)-x^3=8 are x=-1,x=-2,x=4

Find the zeros of (x+2)(2x^2-5x)-x^3=8

The zeros of (x+2)(2x^2-5x)-x^3=8 are x=-1,x=-2,x=4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x + 2) (2 x^{2} - 5 x) - x^{3} = 8

x = - 1, x = - 2, x = 4

Solution steps

(x + 2) (2 x^{2} - 5 x) - x^{3} = 8

Expand

(x + 2) (2 x^{2} - 5 x) - x^{3} : x^{3} - x^{2} - 10 x

x^{3} - x^{2} - 10 x = 8

Move

8

to the left side

x^{3} - x^{2} - 10 x - 8 = 0

Factor

x^{3} - x^{2} - 10 x - 8 : (x + 1) (x + 2) (x - 4)

(x + 1) (x + 2) (x - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x + 2 = 0 or x - 4 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x + 2 = 0 : x = - 2

Solve

x - 4 = 0 : x = 4

The solutions are

x = - 1, x = - 2, x = 4

x, x^{3} + y^{3} + z^{3} = k^{1} - 100

4 x - 2 x^{4} - 2 = 0

x^{5} + 4 x^{3} = 5 x

x, (2 x^{4} \cdot y^{4} - 4 x^{2} \cdot y) = (2 x^{2} \cdot y)

(1 + r)^{6} = 8000

What are the solutions to the equation (x+2)(2x^2-5x)-x^3=8 ?
The solutions to the equation (x+2)(2x^2-5x)-x^3=8 are x=-1,x=-2,x=4
Find the zeros of (x+2)(2x^2-5x)-x^3=8
The zeros of (x+2)(2x^2-5x)-x^3=8 are x=-1,x=-2,x=4