What are the solutions to the equation 320=(x^7)/2 ?

The solutions to the equation 320=(x^7)/2 are x=2\sqrt[7]{5}

Find the zeros of 320=(x^7)/2

The zeros of 320=(x^7)/2 are x=2\sqrt[7]{5}

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320 = \frac{x ^{7}}{2}

x = 275

Decimal

x = 2.51699 \dots

Solution steps

320 = \frac{x ^{7}}{2}

Switch sides

\frac{x ^{7}}{2} = 320

Multiply both sides by

2

x^{7} = 640

For

x^{n} = f (a)

, n is odd, the solution is

x = n f (a)

x = 7640

7640 = 275

x = 275

x^{3} - x - 990 = 0

(2 x^{2} - 1) (x + 2) (x^{2} - 2 x) (x^{3} + 5) = 0

(3 x^{2} + 2 x + 4)^{2} = (x^{2} - 4)^{2}

x^{3} - 10 x^{2} - 784 = 0

x^{4} = 3184

What are the solutions to the equation 320=(x^7)/2 ?
The solutions to the equation 320=(x^7)/2 are x=2\sqrt[7]{5}
Find the zeros of 320=(x^7)/2
The zeros of 320=(x^7)/2 are x=2\sqrt[7]{5}