What are the solutions to the equation 8=(1+r)^{12} ?

The solutions to the equation 8=(1+r)^{12} are r=\sqrt[4]{2}-1,r=-\sqrt[4]{2}-1

Find the zeros of 8=(1+r)^{12}

The zeros of 8=(1+r)^{12} are r=\sqrt[4]{2}-1,r=-\sqrt[4]{2}-1

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8 = (1 + r)^{12}

Decimal Notation

r = 0.18920 \dots, r = - 2.18920 \dots

Solution steps

8 = (1 + r)^{12}

Switch sides

(1 + r)^{12} = 8

For

(g (x))^{n} = f (a)

, n is even, the solutions are

Solve

The solutions are

x^{99} = 13000000

3 x^{2} - 15 x^{12} = 0

x^{3} - 4 x^{2} + 2 = 0

x^{3} - 2 x^{2} + 4 x + 10 = 0

x^{22} x - 24 = 0

What are the solutions to the equation 8=(1+r)^{12} ?
The solutions to the equation 8=(1+r)^{12} are r=\sqrt[4]{2}-1,r=-\sqrt[4]{2}-1
Find the zeros of 8=(1+r)^{12}
The zeros of 8=(1+r)^{12} are r=\sqrt[4]{2}-1,r=-\sqrt[4]{2}-1