What are the solutions to the equation solvefor x,x^5+5r^2-1=0 ?

The solutions to the equation solvefor x,x^5+5r^2-1=0 are x=\sqrt[5]{-5r^2+1}

Find the zeros of solvefor x,x^5+5r^2-1=0

The zeros of solvefor x,x^5+5r^2-1=0 are x=\sqrt[5]{-5r^2+1}

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solve for

x, x^{5} + 5 r^{2} - 1 = 0

Solution steps

x^{5} + 5 r^{2} - 1 = 0

Move

5 r^{2}

to the right side

x^{5} - 1 = - 5 r^{2}

Move

1

to the right side

x^{5} = - 5 r^{2} + 1

For

x^{n} = f (a)

, n is odd, the solution is

(3 x^{3} - 2 x^{2} - 7 x) = 2

x^{3} - x^{2} - 8 x + 12 = 0

x^{3} + 3 x + 1 = 0

\frac{( x - 3 ) ^{3}}{3} = 81

(n - 2)^{3} = 8

What are the solutions to the equation solvefor x,x^5+5r^2-1=0 ?
The solutions to the equation solvefor x,x^5+5r^2-1=0 are x=\sqrt[5]{-5r^2+1}
Find the zeros of solvefor x,x^5+5r^2-1=0
The zeros of solvefor x,x^5+5r^2-1=0 are x=\sqrt[5]{-5r^2+1}