What is log_{x}(((x+4)^2)/(2x+5))<0 ?

The solution to log_{x}(((x+4)^2)/(2x+5))<0 is 0<x<1

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log_{x}(((x+4)^2)/(2x+5))<0

lo g_{x} (\frac{( x + 4 ) ^{2}}{2 x + 5}) < 0

0 < x < 1

Interval Notation

(0, 1)

Solution steps

lo g_{x} (\frac{( x + 4 ) ^{2}}{2 x + 5}) < 0

Apply log rules

0 < x < 1

q^{2} + 7 q + 10

9 y + 5 y + 11 = 16 - 6 y

5 t^{4} + 5 t^{3} - 210 t^{2}

\frac{2 x - 3}{5} - \frac{x}{2} = 1 - \frac{x - 1}{4}

\frac{2 ( 8.99 x 1 0 ^{9} ) ( \frac{x}{2.55} )}{0.184} = 36

What is log_{x}(((x+4)^2)/(2x+5))<0 ?
The solution to log_{x}(((x+4)^2)/(2x+5))<0 is 0<x<1