What are the solutions to the equation -x^3+27x-54x=0 ?

The solutions to the equation -x^3+27x-54x=0 are x=0,x=3sqrt(3)i,x=-3sqrt(3)i

Find the zeros of -x^3+27x-54x=0

The zeros of -x^3+27x-54x=0 are x=0,x=3sqrt(3)i,x=-3sqrt(3)i

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- x^{3} + 27 x - 54 x = 0

x = 0, x = 33 i, x = - 33 i

Solution steps

- x^{3} + 27 x - 54 x = 0

Factor

- x^{3} + 27 x - 54 x : x (- x^{2} - 27)

x (- x^{2} - 27) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or - x^{2} - 27 = 0

Solve

- x^{2} - 27 = 0 : x = 33 i, x = - 33 i

The solutions are

x = 0, x = 33 i, x = - 33 i

(x - 2)^{6} + (x - 4)^{6} = 64

x, f (x)^{4} + f (- x)^{4} = x^{2000}

2 a^{3} - 3 a^{2} + 2 a + 1 = 0

2 x^{5} - 5 x^{4} + 10 x + 3 = 0

1 x^{3} - 7 x + 6 = 0

What are the solutions to the equation -x^3+27x-54x=0 ?
The solutions to the equation -x^3+27x-54x=0 are x=0,x=3sqrt(3)i,x=-3sqrt(3)i
Find the zeros of -x^3+27x-54x=0
The zeros of -x^3+27x-54x=0 are x=0,x=3sqrt(3)i,x=-3sqrt(3)i