What are the solutions to the equation -8x-12+x^3+x^2=0 ?

The solutions to the equation -8x-12+x^3+x^2=0 are x=-2,x=3

Find the zeros of -8x-12+x^3+x^2=0

The zeros of -8x-12+x^3+x^2=0 are x=-2,x=3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 8 x - 12 + x^{3} + x^{2} = 0

x = - 2, x = 3

Solution steps

- 8 x - 12 + x^{3} + x^{2} = 0

Write in the standard form

a_{n} x^{n} + \dots + a_{1} x + a_{0} = 0

x^{3} + x^{2} - 8 x - 12 = 0

Factor

x^{3} + x^{2} - 8 x - 12 : (x + 2)^{2} (x - 3)

(x + 2)^{2} (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 2 = 0 or x - 3 = 0

Solve

x + 2 = 0 : x = - 2

Solve

x - 3 = 0 : x = 3

The solutions are

x = - 2, x = 3

0 = x^{3} - x + 1

x, 1 f = (6 x^{2} + 7 x)^{4}

j^{2} + 2 j^{12} + 2 j^{22} = 1

x^{5} = 1.96

4 y^{4} + 8 y^{2} - 225 = 0

What are the solutions to the equation -8x-12+x^3+x^2=0 ?
The solutions to the equation -8x-12+x^3+x^2=0 are x=-2,x=3
Find the zeros of -8x-12+x^3+x^2=0
The zeros of -8x-12+x^3+x^2=0 are x=-2,x=3