What are the solutions to the equation 9x^4-3x^3+34x^2-12x-8=0 ?

The solutions to the equation 9x^4-3x^3+34x^2-12x-8=0 are x=-1/3 ,x= 2/3 ,x=2i,x=-2i

Find the zeros of 9x^4-3x^3+34x^2-12x-8=0

The zeros of 9x^4-3x^3+34x^2-12x-8=0 are x=-1/3 ,x= 2/3 ,x=2i,x=-2i

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9 x^{4} - 3 x^{3} + 34 x^{2} - 12 x - 8 = 0

x = - \frac{1}{3}, x = \frac{2}{3}, x = 2 i, x = - 2 i

Solution steps

9 x^{4} - 3 x^{3} + 34 x^{2} - 12 x - 8 = 0

Factor

9 x^{4} - 3 x^{3} + 34 x^{2} - 12 x - 8 : (3 x + 1) (3 x - 2) (x^{2} + 4)

(3 x + 1) (3 x - 2) (x^{2} + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 x + 1 = 0 or 3 x - 2 = 0 or x^{2} + 4 = 0

Solve

3 x + 1 = 0 : x = - \frac{1}{3}

Solve

3 x - 2 = 0 : x = \frac{2}{3}

Solve

x^{2} + 4 = 0 : x = 2 i, x = - 2 i

The solutions are

x = - \frac{1}{3}, x = \frac{2}{3}, x = 2 i, x = - 2 i

a^{3} - 44 a + 48 = 0

x^{3} + x = 0

x + x^{3} = 0

(x + 1)^{3} = 64

x^{3} + 4 x - 1 = 0

What are the solutions to the equation 9x^4-3x^3+34x^2-12x-8=0 ?
The solutions to the equation 9x^4-3x^3+34x^2-12x-8=0 are x=-1/3 ,x= 2/3 ,x=2i,x=-2i
Find the zeros of 9x^4-3x^3+34x^2-12x-8=0
The zeros of 9x^4-3x^3+34x^2-12x-8=0 are x=-1/3 ,x= 2/3 ,x=2i,x=-2i