What are the solutions to the equation (4^2-x)^4=16 ?

The solutions to the equation (4^2-x)^4=16 are x=14,x=18

Find the zeros of (4^2-x)^4=16

The zeros of (4^2-x)^4=16 are x=14,x=18

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(4^{2} - x)^{4} = 16

x = 14, x = 18

Solution steps

(4^{2} - x)^{4} = 16

For

(g (x))^{n} = f (a)

, n is even, the solutions are

Solve

The solutions are

x = 14, x = 18

2 = (\frac{1 + r}{100})^{6}

2 x^{4} - x^{3} - 3 x^{2} - 9 x - 4 = 0

(x) = 0.04 x^{3} - 2 x^{2} + 60 x + 200

m^{3} + 6 m^{2} + m + 8 = 0

4 x^{3} + x = x

What are the solutions to the equation (4^2-x)^4=16 ?
The solutions to the equation (4^2-x)^4=16 are x=14,x=18
Find the zeros of (4^2-x)^4=16
The zeros of (4^2-x)^4=16 are x=14,x=18