What is factor 8x^3y^2+4x^2y-12x^4y ?

The solution to factor 8x^3y^2+4x^2y-12x^4y is 4x^2y(2xy+1-3x^2)

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factor 8x^3y^2+4x^2y-12x^4y

factor

8 x^{3} y^{2} + 4 x^{2} y - 12 x^{4} y

4 x^{2} y (2 x y + 1 - 3 x^{2})

Solution steps

8 x^{3} y^{2} + 4 x^{2} y - 12 x^{4} y

Apply exponent rule:

a^{b + c} = a^{b} a^{c}

x^{3} y^{2} = x^{2} x yy, x^{4} y = x^{2} x^{2} y

= 8 x^{2} x yy + 4 x^{2} y - 12 x^{2} x^{2} y

Rewrite

- 12

3 \cdot 4

Rewrite

8

2 \cdot 4

= 2 \cdot 4 x^{2} x yy + 4 x^{2} y + 3 \cdot 4 x^{2} x^{2} y

Factor out common term

4 x^{2} y

= 4 x^{2} y (2 x y + 1 - 3 x^{2})

(2 x + 1)^{2} = 3

(x + 3)^{2} = 100

\frac{26 - 4 x}{x} < 9

496 - 624

8 x^{2} + 18 x - 5

What is factor 8x^3y^2+4x^2y-12x^4y ?
The solution to factor 8x^3y^2+4x^2y-12x^4y is 4x^2y(2xy+1-3x^2)