What are the solutions to the equation 1+1(x^2)/(3^2)x^5=n ?

The solutions to the equation 1+1(x^2)/(3^2)x^5=n are x=\sqrt[7]{9}\sqrt[7]{n-1}

Find the zeros of 1+1(x^2)/(3^2)x^5=n

The zeros of 1+1(x^2)/(3^2)x^5=n are x=\sqrt[7]{9}\sqrt[7]{n-1}

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1 + 1 \frac{x ^{2}}{3 ^{2}} x^{5} = n

Solution steps

1 + 1 \cdot \frac{x ^{2}}{3 ^{2}} x^{5} = n

Move

1

to the right side

1 \cdot \frac{x ^{2}}{3 ^{2}} x^{5} = n - 1

Simplify

\frac{x ^{7}}{9} = n - 1

Multiply both sides by

9

\frac{9 x ^{7}}{9} = 9 (n - 1)

x^{7} = 9 (n - 1)

For

x^{n} = f (a)

, n is odd, the solution is

Simplify

c^{4} = 9

22 x x^{2} x + 9 = (43) 6

- 6 (x + 7)^{4} + 5 = 0

x^{3} - 135 x^{2} + 5400 x - 54000 = 0

x^{4} - 2 x^{3} - 3 x^{2} = 0

What are the solutions to the equation 1+1(x^2)/(3^2)x^5=n ?
The solutions to the equation 1+1(x^2)/(3^2)x^5=n are x=\sqrt[7]{9}\sqrt[7]{n-1}
Find the zeros of 1+1(x^2)/(3^2)x^5=n
The zeros of 1+1(x^2)/(3^2)x^5=n are x=\sqrt[7]{9}\sqrt[7]{n-1}