What are the solutions to the equation d^4-6d^3+13d^2-12d+4=0 ?

The solutions to the equation d^4-6d^3+13d^2-12d+4=0 are d=1,d=2

Find the zeros of d^4-6d^3+13d^2-12d+4=0

The zeros of d^4-6d^3+13d^2-12d+4=0 are d=1,d=2

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d^{4} - 6 d^{3} + 13 d^{2} - 12 d + 4 = 0

d = 1, d = 2

Solution steps

d^{4} - 6 d^{3} + 13 d^{2} - 12 d + 4 = 0

Factor

d^{4} - 6 d^{3} + 13 d^{2} - 12 d + 4 : (d - 1)^{2} (d - 2)^{2}

(d - 1)^{2} (d - 2)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

d - 1 = 0 or d - 2 = 0

Solve

d - 1 = 0 : d = 1

Solve

d - 2 = 0 : d = 2

The solutions are

d = 1, d = 2

780 n^{2} + 26 n^{3} = 2999134

x^{3} - 3 x^{2} - 41 x = 0

y^{3} y - 10 = 3

- 24 x^{120} = - x

y = y^{3}

What are the solutions to the equation d^4-6d^3+13d^2-12d+4=0 ?
The solutions to the equation d^4-6d^3+13d^2-12d+4=0 are d=1,d=2
Find the zeros of d^4-6d^3+13d^2-12d+4=0
The zeros of d^4-6d^3+13d^2-12d+4=0 are d=1,d=2