What are the solutions to the equation (d^2+1)^3=0 ?

The solutions to the equation (d^2+1)^3=0 are d=i,d=-i

Find the zeros of (d^2+1)^3=0

The zeros of (d^2+1)^3=0 are d=i,d=-i

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(d^{2} + 1)^{3} = 0

d = i, d = - i

Solution steps

(d^{2} + 1)^{3} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

Solve

d^{2} + 1 = 0 : d = i, d = - i

The solutions are

d = i, d = - i

(x + 5)^{3} = \frac{- 64}{125}

n (n^{2} + 1) = 336

(x^{2} + 1)^{2} - 4 x^{2} = 0

x^{4} - 2 x^{2} = 0

y^{4} - 5 y^{2} + 4 = 0

What are the solutions to the equation (d^2+1)^3=0 ?
The solutions to the equation (d^2+1)^3=0 are d=i,d=-i
Find the zeros of (d^2+1)^3=0
The zeros of (d^2+1)^3=0 are d=i,d=-i