What are the solutions to the equation a^3=1 ?

The solutions to the equation a^3=1 are a=1,a=-1/2+(sqrt(3))/2 i,a=-1/2-(sqrt(3))/2 i

Find the zeros of a^3=1

The zeros of a^3=1 are a=1,a=-1/2+(sqrt(3))/2 i,a=-1/2-(sqrt(3))/2 i

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a^{3} = 1

a = 1, a = - \frac{1}{2} + \frac{3}{2} i, a = - \frac{1}{2} - \frac{3}{2} i

Solution steps

a^{3} = 1

For

x^{3} = f (a)

the solutions are

a = 1, a = \frac{- 1 + 3 i}{2}, a = \frac{- 1 - 3 i}{2}

Simplify

\frac{- 1 + 3 i}{2} : - \frac{1}{2} + \frac{3}{2} i

Simplify

\frac{- 1 - 3 i}{2} : - \frac{1}{2} - \frac{3}{2} i

a = 1, a = - \frac{1}{2} + \frac{3}{2} i, a = - \frac{1}{2} - \frac{3}{2} i

1 - p^{14} = 0.99

a^{3} = 8

k^{3} - 2 k^{2} + k + 1 = 0

x^{15} = x^{2}

(22 - 15)^{5} = (2 x - 15)^{3}

What are the solutions to the equation a^3=1 ?
The solutions to the equation a^3=1 are a=1,a=-1/2+(sqrt(3))/2 i,a=-1/2-(sqrt(3))/2 i
Find the zeros of a^3=1
The zeros of a^3=1 are a=1,a=-1/2+(sqrt(3))/2 i,a=-1/2-(sqrt(3))/2 i