What are the solutions to the equation (2x-9)(x^2-4)=0 ?

The solutions to the equation (2x-9)(x^2-4)=0 are x=-2,x=2,x= 9/2

Find the zeros of (2x-9)(x^2-4)=0

The zeros of (2x-9)(x^2-4)=0 are x=-2,x=2,x= 9/2

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(2 x - 9) (x^{2} - 4) = 0

x = - 2, x = 2, x = \frac{9}{2}

Decimal Notation

x = - 2, x = 2, x = 4.5

Solution steps

(2 x - 9) (x^{2} - 4) = 0

Factor

(2 x - 9) (x^{2} - 4) : (x + 2) (x - 2) (2 x - 9)

(x + 2) (x - 2) (2 x - 9) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 2 = 0 or x - 2 = 0 or 2 x - 9 = 0

Solve

x + 2 = 0 : x = - 2

Solve

x - 2 = 0 : x = 2

Solve

2 x - 9 = 0 : x = \frac{9}{2}

The solutions are

x = - 2, x = 2, x = \frac{9}{2}

x^{3} - 4 x^{2} - 5 x = 0

x - x^{3} = 1

x^{3} - 6 x + 4 = 0

x^{3} = - 0.49

x^{3} + x^{2} - 4 x = 4

What are the solutions to the equation (2x-9)(x^2-4)=0 ?
The solutions to the equation (2x-9)(x^2-4)=0 are x=-2,x=2,x= 9/2
Find the zeros of (2x-9)(x^2-4)=0
The zeros of (2x-9)(x^2-4)=0 are x=-2,x=2,x= 9/2