What are the solutions to the equation (2x+1)^3=125 ?

The solutions to the equation (2x+1)^3=125 are x=2,x=-7/4+i(5sqrt(3))/4 ,x=-7/4-i(5sqrt(3))/4

Find the zeros of (2x+1)^3=125

The zeros of (2x+1)^3=125 are x=2,x=-7/4+i(5sqrt(3))/4 ,x=-7/4-i(5sqrt(3))/4

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(2 x + 1)^{3} = 125

x = 2, x = - \frac{7}{4} + i \frac{5 3}{4}, x = - \frac{7}{4} - i \frac{5 3}{4}

Solution steps

(2 x + 1)^{3} = 125

For

g^{3} (x) = f (a)

the solutions are

Solve

The solutions are

x = 2, x = - \frac{7}{4} + i \frac{5 3}{4}, x = - \frac{7}{4} - i \frac{5 3}{4}

x^{4} - 9 = 0

z^{4} - 25 = 0

\frac{( x - 4 )}{5} = x^{23} - 5

x^{3} - 6 x^{2} + 3 = 0

2 y^{3} = 5 + 4 y

What are the solutions to the equation (2x+1)^3=125 ?
The solutions to the equation (2x+1)^3=125 are x=2,x=-7/4+i(5sqrt(3))/4 ,x=-7/4-i(5sqrt(3))/4
Find the zeros of (2x+1)^3=125
The zeros of (2x+1)^3=125 are x=2,x=-7/4+i(5sqrt(3))/4 ,x=-7/4-i(5sqrt(3))/4