What are the solutions to the equation (8x^2)(5x^3)=40x ?

The solutions to the equation (8x^2)(5x^3)=40x are x=0,x=i,x=-i,x=-1,x=1

Find the zeros of (8x^2)(5x^3)=40x

The zeros of (8x^2)(5x^3)=40x are x=0,x=i,x=-i,x=-1,x=1

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(8 x^{2}) (5 x^{3}) = 40 x

x = 0, x = i, x = - i, x = - 1, x = 1

Solution steps

(8 x^{2}) (5 x^{3}) = 40 x

Move

40 x

to the left side

8 x^{2} \cdot 5 x^{3} - 40 x = 0

Factor

8 x^{2} \cdot 5 x^{3} - 40 x : 40 x (x^{2} + 1) (x + 1) (x - 1)

40 x (x^{2} + 1) (x + 1) (x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x^{2} + 1 = 0 or x + 1 = 0 or x - 1 = 0

Solve

x^{2} + 1 = 0 : x = i, x = - i

Solve

x + 1 = 0 : x = - 1

Solve

x - 1 = 0 : x = 1

The solutions are

x = 0, x = i, x = - i, x = - 1, x = 1

x^{4} + 8 x^{3} + 30 x^{2} + 56 x - 95 = 0

14.93 (x + 1)^{3} = 20

x^{4} = 4

x^{4} = 9

4 (x)^{3} + x - 1 = 0

What are the solutions to the equation (8x^2)(5x^3)=40x ?
The solutions to the equation (8x^2)(5x^3)=40x are x=0,x=i,x=-i,x=-1,x=1
Find the zeros of (8x^2)(5x^3)=40x
The zeros of (8x^2)(5x^3)=40x are x=0,x=i,x=-i,x=-1,x=1