What are the solutions to the equation b^3-1=7 ?

The solutions to the equation b^3-1=7 are b=2,b=-1+sqrt(3)i,b=-1-sqrt(3)i

Find the zeros of b^3-1=7

The zeros of b^3-1=7 are b=2,b=-1+sqrt(3)i,b=-1-sqrt(3)i

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b^{3} - 1 = 7

b = 2, b = - 1 + 3 i, b = - 1 - 3 i

Solution steps

b^{3} - 1 = 7

Move

1

to the right side

b^{3} = 8

For

x^{3} = f (a)

the solutions are

Simplify

b = 2, b = - 1 + 3 i, b = - 1 - 3 i

x^{3} + 3 x = 0

2 x^{3} - 3 x^{2} - 3 x + 2 = 0

(a^{2})^{2} = 2, a^{1} = 1

x^{3} + 4 x^{2} - 2 x - 8 = 0

r^{5} = 8 r^{2}

What are the solutions to the equation b^3-1=7 ?
The solutions to the equation b^3-1=7 are b=2,b=-1+sqrt(3)i,b=-1-sqrt(3)i
Find the zeros of b^3-1=7
The zeros of b^3-1=7 are b=2,b=-1+sqrt(3)i,b=-1-sqrt(3)i