What are the solutions to the equation solvefor y,y^3=x^3+4x^4-x^5+2x^2-x+1 ?

The solutions to the equation solvefor y,y^3=x^3+4x^4-x^5+2x^2-x+1 are

Find the zeros of solvefor y,y^3=x^3+4x^4-x^5+2x^2-x+1

The zeros of solvefor y,y^3=x^3+4x^4-x^5+2x^2-x+1 are

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solve for

y, y^{3} = x^{3} + 4 x^{4} - x^{5} + 2 x^{2} - x + 1

Solution steps

y^{3} = x^{3} + 4 x^{4} - x^{5} + 2 x^{2} - x + 1

For

x^{3} = f (a)

the solutions are

Simplify

(5 - 2 x)^{3} = - 27

3 x^{4} = 9

x^{4} - 9 = 2 x^{4} + 6 x^{2}

x^{3} - 14 x^{2} - 49 = 0

2 x^{3} - 6 x + 5 = 0

What are the solutions to the equation solvefor y,y^3=x^3+4x^4-x^5+2x^2-x+1 ?
The solutions to the equation solvefor y,y^3=x^3+4x^4-x^5+2x^2-x+1 are
Find the zeros of solvefor y,y^3=x^3+4x^4-x^5+2x^2-x+1
The zeros of solvefor y,y^3=x^3+4x^4-x^5+2x^2-x+1 are