What are the solutions to the equation m^3-2m^2-4m+8=0 ?

The solutions to the equation m^3-2m^2-4m+8=0 are m=2,m=-2

Find the zeros of m^3-2m^2-4m+8=0

The zeros of m^3-2m^2-4m+8=0 are m=2,m=-2

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m^{3} - 2 m^{2} - 4 m + 8 = 0

m = 2, m = - 2

Solution steps

m^{3} - 2 m^{2} - 4 m + 8 = 0

Factor

m^{3} - 2 m^{2} - 4 m + 8 : (m - 2)^{2} (m + 2)

(m - 2)^{2} (m + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

m - 2 = 0 or m + 2 = 0

Solve

m - 2 = 0 : m = 2

Solve

m + 2 = 0 : m = - 2

The solutions are

m = 2, m = - 2

x^{3} = \frac{- 7}{2}

x^{4} + 3 x^{3} - 12 x^{2} + 2 x - 1 = 0

3 x^{3} + x - 10 = 0

x (x - 1) (x + 2)^{3} = 0

14 x^{13} - 14 = 0

What are the solutions to the equation m^3-2m^2-4m+8=0 ?
The solutions to the equation m^3-2m^2-4m+8=0 are m=2,m=-2
Find the zeros of m^3-2m^2-4m+8=0
The zeros of m^3-2m^2-4m+8=0 are m=2,m=-2