What are the solutions to the equation 64t-16t^2=0 ?

The solutions to the equation 64t-16t^2=0 are t=0,t=4

Find the zeros of 64t-16t^2=0

The zeros of 64t-16t^2=0 are t=0,t=4

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64 t - 16 t^{2} = 0

t = 0, t = 4

Solution steps

64 t - 16 t^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 16 t^{2} + 64 t = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 64 \pm 6 4 ^{2} - 4 ( - 16 ) \cdot 0}{2 ( - 16 )}

6 4^{2} - 4 (- 16) \cdot 0 = 64

t_{1, 2} = \frac{- 64 \pm 64}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- 64 + 64}{2 ( - 16 )}, t_{2} = \frac{- 64 - 64}{2 ( - 16 )}

t = \frac{- 64 + 64}{2 ( - 16 )} : 0

t = \frac{- 64 - 64}{2 ( - 16 )} : 4

The solutions to the quadratic equation are:

t = 0, t = 4

0 = x^{2} - 16

lo g_{14} (88.5)

x^{2} + 0.242 x + 0.072 = 0

\frac{6 ^{4}}{4} + \frac{36 \cdot 36}{2} - \frac{12 \cdot 6 ^{3}}{3}

4 x + 6 x = 7

What are the solutions to the equation 64t-16t^2=0 ?
The solutions to the equation 64t-16t^2=0 are t=0,t=4
Find the zeros of 64t-16t^2=0
The zeros of 64t-16t^2=0 are t=0,t=4