What are the solutions to the equation x^5-5x^3+4x=0 ?

The solutions to the equation x^5-5x^3+4x=0 are x=0,x=-1,x=1,x=-2,x=2

Find the zeros of x^5-5x^3+4x=0

The zeros of x^5-5x^3+4x=0 are x=0,x=-1,x=1,x=-2,x=2

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x^{5} - 5 x^{3} + 4 x = 0

x = 0, x = - 1, x = 1, x = - 2, x = 2

Solution steps

x^{5} - 5 x^{3} + 4 x = 0

Factor

x^{5} - 5 x^{3} + 4 x : x (x + 1) (x - 1) (x + 2) (x - 2)

x (x + 1) (x - 1) (x + 2) (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 1 = 0 or x - 1 = 0 or x + 2 = 0 or x - 2 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x - 1 = 0 : x = 1

Solve

x + 2 = 0 : x = - 2

Solve

x - 2 = 0 : x = 2

The solutions are

x = 0, x = - 1, x = 1, x = - 2, x = 2

t^{3} - 6 t^{2} + 6 = 0

x^{3} + 3 x^{2} + 3 x + 18 = 0

x^{6} + 28 x^{3} + 16 = 0

(x + 2)^{3} = 0

x^{3} - 8 x^{2} - 4 x - 48 = 0

What are the solutions to the equation x^5-5x^3+4x=0 ?
The solutions to the equation x^5-5x^3+4x=0 are x=0,x=-1,x=1,x=-2,x=2
Find the zeros of x^5-5x^3+4x=0
The zeros of x^5-5x^3+4x=0 are x=0,x=-1,x=1,x=-2,x=2