What are the solutions to the equation 5=40x^3 ?

The solutions to the equation 5=40x^3 are x= 1/2 ,x=-1/4+(sqrt(3))/4 i,x=-1/4-(sqrt(3))/4 i

Find the zeros of 5=40x^3

The zeros of 5=40x^3 are x= 1/2 ,x=-1/4+(sqrt(3))/4 i,x=-1/4-(sqrt(3))/4 i

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5 = 40 x^{3}

x = \frac{1}{2}, x = - \frac{1}{4} + \frac{3}{4} i, x = - \frac{1}{4} - \frac{3}{4} i

Solution steps

5 = 40 x^{3}

Switch sides

40 x^{3} = 5

Divide both sides by

40

x^{3} = \frac{1}{8}

For

x^{3} = f (a)

the solutions are

Simplify

x = \frac{1}{2}, x = - \frac{1}{4} + \frac{3}{4} i, x = - \frac{1}{4} - \frac{3}{4} i

(2 x + 1)^{3} - 15 = 110

(2 x + 3) \cdot (x - 4) = (x + 2) \cdot (4 x^{2} - 9)

c, x^{3} + 3 x^{2} \cdot y + y^{3} = c^{3}

x^{4} - 15 x^{2} - 16 = 0

x, x^{3} - 19 = y^{3}

What are the solutions to the equation 5=40x^3 ?
The solutions to the equation 5=40x^3 are x= 1/2 ,x=-1/4+(sqrt(3))/4 i,x=-1/4-(sqrt(3))/4 i
Find the zeros of 5=40x^3
The zeros of 5=40x^3 are x= 1/2 ,x=-1/4+(sqrt(3))/4 i,x=-1/4-(sqrt(3))/4 i