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Popular >

4|x-3|>12

Solution

4 ∣ x - 3 ∣ > 12

Solution

x < 0 or x > 6

+1

Interval Notation

(- \infty, 0) \cup (6, \infty)

Solution steps

4 ∣ x - 3 ∣ > 12

Divide both sides by

4

∣ x - 3 ∣ > 3

Apply absolute rule: If

∣ u ∣ > a, a > 0

then

u < - a

or

u > a

x - 3 < - 3 or x - 3 > 3

x - 3 < - 3 or x - 3 > 3

x < 0 or x > 6

Popular Examples

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x^{4} - 6 x^{2} - 16

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8 a (x + y) - (x + y)

Frequently Asked Questions (FAQ)

What is 4|x-3|>12 ?
The solution to 4|x-3|>12 is x<0\lor x>6