What are the solutions to the equation (x^2-4)*(x^2-3x+1)=0 ?

The solutions to the equation (x^2-4)*(x^2-3x+1)=0 are x=-2,x=2,x=(3+sqrt(5))/2 ,x=(3-sqrt(5))/2

Find the zeros of (x^2-4)*(x^2-3x+1)=0

The zeros of (x^2-4)*(x^2-3x+1)=0 are x=-2,x=2,x=(3+sqrt(5))/2 ,x=(3-sqrt(5))/2

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(x^{2} - 4) \cdot (x^{2} - 3 x + 1) = 0

x = - 2, x = 2, x = \frac{3 + 5}{2}, x = \frac{3 - 5}{2}

Decimal Notation

x = - 2, x = 2, x = 2.61803 \dots, x = 0.38196 \dots

Solution steps

(x^{2} - 4) (x^{2} - 3 x + 1) = 0

Factor

(x^{2} - 4) (x^{2} - 3 x + 1) : (x + 2) (x - 2) (x^{2} - 3 x + 1)

(x + 2) (x - 2) (x^{2} - 3 x + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 2 = 0 or x - 2 = 0 or x^{2} - 3 x + 1 = 0

Solve

x + 2 = 0 : x = - 2

Solve

x - 2 = 0 : x = 2

Solve

x^{2} - 3 x + 1 = 0 : x = \frac{3 + 5}{2}, x = \frac{3 - 5}{2}

The solutions are

x = - 2, x = 2, x = \frac{3 + 5}{2}, x = \frac{3 - 5}{2}

x^{8} = \frac{1}{2}

x^{3} - 4 x^{2} - 6 x + 9 = 0

5 z^{2} - 45 = 8 z^{3} - 72 z

x^{3} - 9 x^{2} + 36 x - 36 = 0

x^{3} - 7 x^{2} + 36 = 0

What are the solutions to the equation (x^2-4)*(x^2-3x+1)=0 ?
The solutions to the equation (x^2-4)*(x^2-3x+1)=0 are x=-2,x=2,x=(3+sqrt(5))/2 ,x=(3-sqrt(5))/2
Find the zeros of (x^2-4)*(x^2-3x+1)=0
The zeros of (x^2-4)*(x^2-3x+1)=0 are x=-2,x=2,x=(3+sqrt(5))/2 ,x=(3-sqrt(5))/2