What are the solutions to the equation 3x^4+4x^3-6x^2-12x=0 ?

The solutions to the equation 3x^4+4x^3-6x^2-12x=0 are x=0,x\approx 1.56828…

Find the zeros of 3x^4+4x^3-6x^2-12x=0

The zeros of 3x^4+4x^3-6x^2-12x=0 are x=0,x\approx 1.56828…

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3 x^{4} + 4 x^{3} - 6 x^{2} - 12 x = 0

x = 0, x \approx 1.56828 \dots

Solution steps

3 x^{4} + 4 x^{3} - 6 x^{2} - 12 x = 0

Factor

3 x^{4} + 4 x^{3} - 6 x^{2} - 12 x : x (3 x^{3} + 4 x^{2} - 6 x - 12)

x (3 x^{3} + 4 x^{2} - 6 x - 12) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 3 x^{3} + 4 x^{2} - 6 x - 12 = 0

Solve

3 x^{3} + 4 x^{2} - 6 x - 12 = 0 : x \approx 1.56828 \dots

The solutions are

x = 0, x \approx 1.56828 \dots

16 z^{4} = 1

(\frac{a ^{2}}{3})^{2} + (a)^{2} = 50

k = m^{2} v^{3}

2 x^{4} + 5 x^{3} + 2 x^{2} - 45 x = 0

6 x^{4} - 29 x^{3} + 30 x^{2} = 6 - 11 x

What are the solutions to the equation 3x^4+4x^3-6x^2-12x=0 ?
The solutions to the equation 3x^4+4x^3-6x^2-12x=0 are x=0,x\approx 1.56828…
Find the zeros of 3x^4+4x^3-6x^2-12x=0
The zeros of 3x^4+4x^3-6x^2-12x=0 are x=0,x\approx 1.56828…