What are the solutions to the equation (x^2-1)*(5-x)=0 ?

The solutions to the equation (x^2-1)*(5-x)=0 are x=-1,x=1,x=5

Find the zeros of (x^2-1)*(5-x)=0

The zeros of (x^2-1)*(5-x)=0 are x=-1,x=1,x=5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x^{2} - 1) \cdot (5 - x) = 0

x = - 1, x = 1, x = 5

Solution steps

(x^{2} - 1) (5 - x) = 0

Factor

(x^{2} - 1) (5 - x) : - (x + 1) (x - 1) (x - 5)

- (x + 1) (x - 1) (x - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x - 1 = 0 or x - 5 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x - 1 = 0 : x = 1

Solve

x - 5 = 0 : x = 5

The solutions are

x = - 1, x = 1, x = 5

(x^{2} + 2 x)^{2} - 5 (x^{2} + 2 x) + 6 = 0

a, a^{4} b + 2 c^{5} = d^{1} e

8 m^{3} - 104 m^{2} + 336 m = 0

5 x^{3} - 29 x + 30 = 0

- x^{3} + 3 x^{2} - 24 x + 1 = 0

What are the solutions to the equation (x^2-1)*(5-x)=0 ?
The solutions to the equation (x^2-1)*(5-x)=0 are x=-1,x=1,x=5
Find the zeros of (x^2-1)*(5-x)=0
The zeros of (x^2-1)*(5-x)=0 are x=-1,x=1,x=5