What are the solutions to the equation z^3=-27 ?

The solutions to the equation z^3=-27 are z=-3,z= 3/2-(3sqrt(3))/2 i,z= 3/2+(3sqrt(3))/2 i

Find the zeros of z^3=-27

The zeros of z^3=-27 are z=-3,z= 3/2-(3sqrt(3))/2 i,z= 3/2+(3sqrt(3))/2 i

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z^{3} = - 27

z = - 3, z = \frac{3}{2} - \frac{3 3}{2} i, z = \frac{3}{2} + \frac{3 3}{2} i

Solution steps

z^{3} = - 27

For

x^{3} = f (a)

the solutions are

Simplify

z = - 3, z = \frac{3}{2} - \frac{3 3}{2} i, z = \frac{3}{2} + \frac{3 3}{2} i

(2 x^{3} + 7)^{2} + (2 x^{2} + 3)^{3} = 6 x^{2} + 6 x

n^{3} + 3 n^{2} + 2 n = 8436

x, y^{2} = x^{2} - x^{4}

x^{4} + x^{2} - 90 = 0

12 x^{3} - x^{2} + 13 = 0

What are the solutions to the equation z^3=-27 ?
The solutions to the equation z^3=-27 are z=-3,z= 3/2-(3sqrt(3))/2 i,z= 3/2+(3sqrt(3))/2 i
Find the zeros of z^3=-27
The zeros of z^3=-27 are z=-3,z= 3/2-(3sqrt(3))/2 i,z= 3/2+(3sqrt(3))/2 i