What are the solutions to the equation x(x^2+6x+9)=4(x+3) ?

The solutions to the equation x(x^2+6x+9)=4(x+3) are x=-3,x=1,x=-4

Find the zeros of x(x^2+6x+9)=4(x+3)

The zeros of x(x^2+6x+9)=4(x+3) are x=-3,x=1,x=-4

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x (x^{2} + 6 x + 9) = 4 (x + 3)

x = - 3, x = 1, x = - 4

Solution steps

x (x^{2} + 6 x + 9) = 4 (x + 3)

Move

4 (x + 3)

to the left side

x (x^{2} + 6 x + 9) - 4 (x + 3) = 0

Factor

x (x^{2} + 6 x + 9) - 4 (x + 3) : (x + 3) (x - 1) (x + 4)

(x + 3) (x - 1) (x + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 3 = 0 or x - 1 = 0 or x + 4 = 0

Solve

x + 3 = 0 : x = - 3

Solve

x - 1 = 0 : x = 1

Solve

x + 4 = 0 : x = - 4

The solutions are

x = - 3, x = 1, x = - 4

3 x^{4} - 32 x^{3} + 118 x^{2} - 152 x - 65 = 0

x^{4} - 3 x^{3} + 2 x^{2} = 0

6 x^{3} - 11 x^{2} + x - 6 = 0

\frac{5 x ^{3}}{4 + 4} = 44

x^{5} = 0.2

What are the solutions to the equation x(x^2+6x+9)=4(x+3) ?
The solutions to the equation x(x^2+6x+9)=4(x+3) are x=-3,x=1,x=-4
Find the zeros of x(x^2+6x+9)=4(x+3)
The zeros of x(x^2+6x+9)=4(x+3) are x=-3,x=1,x=-4