What are the solutions to the equation 7x^2+6x+1=0 ?

The solutions to the equation 7x^2+6x+1=0 are x=(-3+sqrt(2))/7 ,x=-(3+sqrt(2))/7

Find the zeros of 7x^2+6x+1=0

The zeros of 7x^2+6x+1=0 are x=(-3+sqrt(2))/7 ,x=-(3+sqrt(2))/7

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7 x^{2} + 6 x + 1 = 0

x = \frac{- 3 + 2}{7}, x = - \frac{3 + 2}{7}

Solution steps

7 x^{2} + 6 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 7 \cdot 1}{2 \cdot 7}

6^{2} - 4 \cdot 7 \cdot 1 = 22

x_{1, 2} = \frac{- 6 \pm 2 2}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- 6 + 2 2}{2 \cdot 7}, x_{2} = \frac{- 6 - 2 2}{2 \cdot 7}

x = \frac{- 6 + 2 2}{2 \cdot 7} : \frac{- 3 + 2}{7}

x = \frac{- 6 - 2 2}{2 \cdot 7} : - \frac{3 + 2}{7}

The solutions to the quadratic equation are:

x = \frac{- 3 + 2}{7}, x = - \frac{3 + 2}{7}

\frac{y ^{3}}{y ^{2}}

5 n^{2} + 22 n + 24

5 x^{2} + 4 x - 6 = 0

\frac{1}{2} \cdot 3

x^{2} - 16 \leq 0

What are the solutions to the equation 7x^2+6x+1=0 ?
The solutions to the equation 7x^2+6x+1=0 are x=(-3+sqrt(2))/7 ,x=-(3+sqrt(2))/7
Find the zeros of 7x^2+6x+1=0
The zeros of 7x^2+6x+1=0 are x=(-3+sqrt(2))/7 ,x=-(3+sqrt(2))/7