What are the solutions to the equation -3x^2+x^3=4x ?

The solutions to the equation -3x^2+x^3=4x are x=0,x=-1,x=4

Find the zeros of -3x^2+x^3=4x

The zeros of -3x^2+x^3=4x are x=0,x=-1,x=4

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- 3 x^{2} + x^{3} = 4 x

x = 0, x = - 1, x = 4

Solution steps

- 3 x^{2} + x^{3} = 4 x

Move

4 x

to the left side

- 3 x^{2} + x^{3} - 4 x = 0

Factor

- 3 x^{2} + x^{3} - 4 x : x (x + 1) (x - 4)

x (x + 1) (x - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 1 = 0 or x - 4 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x - 4 = 0 : x = 4

The solutions are

x = 0, x = - 1, x = 4

(z + 2)^{3} = z^{2} + 5 z + 2

m^{3} - 10 m + 1 = 0

r^{4} - 6 0^{3} - 20600 r^{2} + 2166000 r + 32490000 = 0

x^{3} - x = \frac{1}{4} x^{2} - \frac{1}{4}

x^{3} + 3 x^{2} + 3 x - 7 = 0

What are the solutions to the equation -3x^2+x^3=4x ?
The solutions to the equation -3x^2+x^3=4x are x=0,x=-1,x=4
Find the zeros of -3x^2+x^3=4x
The zeros of -3x^2+x^3=4x are x=0,x=-1,x=4